There are a total of numCourses courses you have to take, labeled from 0 to numCourses - 1. You are given an array prerequisites where prerequisites[i] = [ai, bi] indicates that you must take course bi first if you want to take course ai.
For example, the pair [0, 1], indicates that to take course 0 you have to first take course 1.
Return true if you can finish all courses. Otherwise, return false.
Example 1:
Input: numCourses = 2, prerequisites = [[1,0]]
Output: true
Explanation: There are a total of 2 courses to take.
To take course 1 you should have finished course 0. So it is possible.
Example 2:
Input: numCourses = 2, prerequisites = [[1,0],[0,1]]
Output: false
Explanation: There are a total of 2 courses to take.
To take course 1 you should have finished course 0, and to take course 0 you should also have finished course 1. So it is impossible.
Constraints:
1 <= numCourses <= 2000
0 <= prerequisites.length <= 5000
prerequisites[i].length == 2
0 <= ai, bi < numCourses
All the pairs prerequisites[i] are unique.
/** * @param{number} numCourses * @param{number[][]} prerequisites * @return{boolean} */varcanFinish=function(numCourses, prerequisites) {constincommingEdges=newArray(numCourses).fill(0);constadjs= {};// create adjacent listx// couting num of edges incommingfor (const [here,there] of prerequisites) {if (adjs[here] ===undefined) adjs[here] = []; adjs[here].push(there); incommingEdges[there] +=1; }constq= [];// find vertexes incomming edges 0for (let i =0; i <incommingEdges.length; i++) {if (incommingEdges[i] ===0) {q.push(i); } }// iterate queue until there is no vertex, whose the number of incomming edges is equal to zeroconstseq= [];while (q.length>0) {consthere=q.shift();seq.push(here);constadj= adjs[here] ?? [];// if (adj === undefined) continue;for (constthereof adj) { incommingEdges[there] -=1;if (incommingEdges[there] ===0) {q.push(there); } } }returnseq.length=== numCourses ?true:false;};