268. Missing Number

with xor

/**
 * @param {number[]} nums
 * @return {number}
 */
var missingNumber = function(nums) {
    
    let ans = nums.length;
    for (let i = 0; i < nums.length; i++) {
        ans = ans^i^nums[i];
    }

    return ans;
};

time: O(N)

space: O(1)

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